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path-sum.py
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37 lines (35 loc) · 1.21 KB
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# https://leetcode.com/problems/path-sum/
#
# Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
#
# For example:
# Given the below binary tree and sum = 22,
# 5
# / \
# 4 8
# / / \
# 11 13 4
# / \ \
# 7 2 1
# return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
# Definition for a binary tree node
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
# @param root, a tree node
# @param sum, an integer
# @return a boolean
def hasPathSum(self, root, sum):
if root == None:
return False
elif root.left == None and root.right == None :
return root.val == sum
elif root.left == None:
return self.hasPathSum(root.right , sum - root.val)
elif root.right == None:
return self.hasPathSum(root.left , sum - root.val)
else:
return self.hasPathSum(root.left,sum -root.val) or self.hasPathSum(root.right , sum - root.val)